Answer:
The answer is the second figure and the vertices of Δ R'S'T' are:
R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)
Explanation:
* Lets revise some transformation
- If point (x , y) reflected across the x-axis
∴ Its image is (x , -y)
- If point (x , y) reflected across the y-axis
∴ Its image is (-x , y)
- If point (x , y) reflected across the line y = x
∴ Its image is (y , x)
- If point (x , y) reflected across the line y = -x
∴ Its image is (-y , -x)
- Now we can solve the problem
∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST
- The triangle RST is reflected over the y-axis
- According to the rule above the signs of x-coordinates will change
∵ R = (6 , 6)
∴ Its image is (-6 , 6)
∵ S = (3 , -6)
∴ Its image is (-3 , -6)
∵ T = (0 , 3)
∴ Its image is (0 , 3)
* Now lets look to the figure to find the correct answers
- The image of Δ RST is ΔR'S'T'
∵ The vertices of the image of ΔRST are:
R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)
* The answer is the second figure