Question

Find the axis of symmetry of the graph of the function.

f(x) = 2x^2 - 16x + 27

Answer 1

the axis of symmetry is x = 4

Explanation:

The three coefficients of the polynomial f(x) = 2x^2 - 16x + 27 are a= 2, b = -16 and c = 27. -b

The formula for the axis of symmetry is x = ------------

2a

-(-16)

which here is x = ------------ = 4

2(2)

The equation of the axis of symmetry is x = 4.