Question

Suppose the tourist in question #1 instead threw the rock with an initial velocity of 8.0

m/s (down). Determine the velocity and displacement of the rock at 4.0 s (Remember
the v; is down and must become a -8.0 m/s)​

Answer 1

Explanation:u=8m/s, a=8m/s*s, t=4s

Using v= u + at

v=8+-8*4

v=-24m/s

Displacement=s

Using s=½(u+v)t

s=½(8-24)4

s=½*-16*4

s=-8*4

s=32m( you can solve without observing the negative sign)