Question

Need asap !

a television of mass 15 kg sits on a table the coefficient of static friction between the table and the television is 0.35 what is the minimum applied force that will cause the television to slide?

a. 79 n

b. 38 n

c. 147 n

d. 51 n

Answer 1

The answer is D) 51 N

Answer 2

D. 51 N. The minimum applied force that will cause the television slide is 51 N.

In order to solve this problem we have to use the force of static friction equation Fs = μs*n, where μs is the coefficient of static friction, and n is the normal force m*g.

With μs = 0.35, and n = 15kg*9.8m/s² = 147 N

Fs = (0.35)(147 N)

Fs = 51.45 N

Fs ≅ 51 N