Question

Which equation represents a circle with a center Jat (-3, -5) and a radius of 6 units?

(x - 3)2 + (y – 5)2 = 6
(x - 3)2 + (y – 5)2 = 36
(x + 3)2 + (y + 5)2 = 6
(x + 3)2 + (y + 5)2 = 36

Answer 1

D. (x + 3)^2 + (y + 5)^2 = 36

Step-by-step explanation:

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Answer 2

`\large\boxed{(x+3)^2+(y+5)^2=36}`

Explanation:

The standard form of an equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

(h, k) - center

r - radius

We have the center at (-3, -5) and the radius r = 6. Substitute:

`(x-(-3))^2+(y-(-5))^2=6^2\\\\(x+3)^2+(y+5)^2=36`