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What is the value of b in the equation 3b + 2(b - 1) =8

User Xavier D
by
6.5k points

2 Answers

7 votes

ANSWER

The value of b is 2

EXPLANATION

The given linear equation in b is


3b + 2(b - 1) = 8

We expand to get:


3b + 2b - 2= 8

We now group similar terms to obtain:


3b + 2b = 8 + 2

Combine the similar terms now to obtain:


5b = 10

Divide both sides by 5 to get:


b = (10)/(5)

This simplifies to:


b = 2

User Prasutagus
by
7.2k points
3 votes

Answer:

b = 2

Explanation:

In order to find the value of b, we have to isolate b on one side of equation first

So,


3b+2(b-1)=8

Multiplying 2 with b-1


3b+2b-2=8\\5b-2=8

Adding 2 on both sides


5b-2+2=8+2\\5b=10

Dividing by 5 on both sides


(5b)/(5)=(10)/(5) \\b=2

So the value of b is 2 ..

User Sartaj Singh Gill
by
8.1k points