108k views
2 votes
Trapezoid ABCD is reflected over the line y = x. What rule shows the input and output of the reflection, and what is the new coordinate of A'? Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1. (x, y) ? (y, ?x); A' is at (1, 5) (x, y) ? (y, x); A' is at (1, ?5) (x, y) ? (?x, y); A' is at (5, 1) (x, y) ? (?x, ?y); A' is at (5, ?1)

User Deloreyk
by
7.7k points

2 Answers

7 votes

Answer:

(x,y)→(y,x); A' is at (1, −5)

Explanation:

Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.

(x,y)→(y,−x); A' is at (1, 5)

(x,y)→(y,x); A' is at (1, −5)

(x,y)→(−x,y); A' is at (5, 1)

(x,y)→(−x,−y); A' is at (5, −1)

This is the complete question and your answer is :

(x,y)→(y,x); A' is at (1, −5)

User Brrrr
by
7.6k points
4 votes

Answer:

  1. (x, y) ⇒ (y, x)
  2. A'(1, -4), B'(3, -4), C'(3, -2), D'(1, -1)

Explanation:

Reflection across the line y=x swaps the x- and y-coordinates.

A(-5, 1) becomes A'(1, -5), for example. The coordinates of the other points are swapped in similar fashion.

Trapezoid ABCD is reflected over the line y = x. What rule shows the input and output-example-1
User HMD
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories