Question

Trapezoid ABCD is reflected over the line y = x. What rule shows the input and output of the reflection, and what is the new coordinate of A'? Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1. (x, y) ? (y, ?x); A' is at (1, 5) (x, y) ? (y, x); A' is at (1, ?5) (x, y) ? (?x, y); A' is at (5, 1) (x, y) ? (?x, ?y); A' is at (5, ?1)

Answer 1

(x,y)→(y,x); A' is at (1, −5)

Explanation:

Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.

(x,y)→(y,−x); A' is at (1, 5)

(x,y)→(y,x); A' is at (1, −5)

(x,y)→(−x,y); A' is at (5, 1)

(x,y)→(−x,−y); A' is at (5, −1)

This is the complete question and your answer is :

(x,y)→(y,x); A' is at (1, −5)

Answer 2

1. (x, y) ⇒ (y, x)
2. A'(1, -4), B'(3, -4), C'(3, -2), D'(1, -1)

Explanation:

Reflection across the line y=x swaps the x- and y-coordinates.

A(-5, 1) becomes A'(1, -5), for example. The coordinates of the other points are swapped in similar fashion.