Question

How much potassium chlorate (KCIO3) must decompose in order to produce 150 grams of oxygen gas (O2)?

Potassium chlorate decomposes according to the following balanced equation:
2KCIO3 + heat → 2KCI+ 3O2​

Answer 1

765.95 grams.

Step-by-step explanation:

2 moles of KClO3 produce 3 moles of oxygen.

Using molar masses:

2 * 122.545 g of KCLO3 produces 47.997 grams of oxygen.

47.997 g O2 is produced from 245.09 g KCLO3

150 g .......................................... 150 * 245.09 / 47.997

= 765.95 grams.