Answer:
dy/dx= cos(ln(x))/x
Explanation:
y=sin(ln(x)) given
We have to use chain rule to differentiate!
Let u=ln(x) then du/dx=1/x
So we have
if y=sin(ln(x)) then y=sin(u) and dy/dx=dy/du * du/dx=cos(u) *1/x
where again u=ln(x) so
dy/dx=cos(ln(x)) *1/x
dy/dx=cos(ln(x))/x
I hope I have the right intepretation because I do see a ? in between sin and (ln(x)) .