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Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

simple interest per year, and she invested the rest in an account that paid 5% simple interest per year. After one year, she received a total of %560 in interest. How much did she invest in each account?

User Storo
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1 Answer

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Answer:

In the account that paid 6% Susan invest
\$6,000

In the account that paid 5% Susan invest
\$4,000

Explanation:

we know that

The simple interest formula is equal to


I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have


t=1\ years\\ P=\$x\\r=0.06

substitute in the formula above


I1=x(0.06*1)


I1=0.06x

Part b) account that paid 5% simple interest per year

in this problem we have


t=1\ years\\ P=\$10,000-\$x\\r=0.05

substitute in the formula above


I2=(10,000-x)(0.05*1)


I2=500-0.05x

we know that


I1+I2=\$560

substitute and solve for x


0.06x+500-0.05x=560


0.01x=560-500


0.01x=60


x=\$6.000

therefore

In the account that paid 6% Susan invest
\$6,000

In the account that paid 5% Susan invest
\$4,000

User Kingoleg
by
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