For this case we have that the area of the kite is given by the area of two triangles, the triangles share the same base of 3 + 3 = 6 meters and one has height of 2m and the other height of 4m.
So, the total area is given by:
![A = \frac {1} {2} * 6 * 2 + \frac {1} {2} * 6 * 4\\A = \frac {1} {2} 12+ \frac {1} {2} *24\\A = 6 + 12\\A = 18](https://img.qammunity.org/2020/formulas/mathematics/high-school/41hvt1swtbzi4x93pnud5appo2rzn571xb.png)
Thus, the area of the kite is
![18m ^ 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/7zjfb68nojs39rpc08xsgrtmmei97vre4h.png)
ANswer:
![18m ^ 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/7zjfb68nojs39rpc08xsgrtmmei97vre4h.png)