Question

A uniform conducting rod of length 22 cm has a potential difference across its ends equal to 41 mV (millivolts). What is the magnitude of the electric field inside the conductor in units of N/C?

Answer 1

0.186 N/C

Step-by-step explanation:

The relationship between electric field strength and potential difference is:

`E=(\Delta V)/(d)`

where

E is the electric field strength

`\Delta V` is the potential difference

d is the distance

Here we have

`\Delta V=41 mV=0.041 V`

d = 22 cm = 0.22 m

So the electric field magnitude is

`E=(0.041 V)/(0.22 m)=0.186 N/C`