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If the force of friction is 2.6 Newton’s, what is the value of acceleration of the box?
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If the force of friction is 2.6 Newton’s, what is the value of acceleration of the box?

If the force of friction is 2.6 Newton’s, what is the value of acceleration of the-example-1
User Mark Rhodes
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1 Answer

5 votes

  • force=massxacceleration
  • aceleration =force /mass
  • the resultant force =the acting force on the object-the fictional force
  • therefore the resultant force=25-2.6=22.4N
  • therefore the acceleration=22.4/7=3.2m/sec^2
User Senshin
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