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computing the probability of rolling two dice in succession face value of two rolls are added together is the sum greater than 7

User Clizzin
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5 votes

Answer:

5/12 ≈ 0.41667

Explanation:

If the first die rolls a 1 and the second die rolls a 1, then the sum is 2.

If the first die rolls a 1 and the second die rolls a 2, then the sum is 3.

Repeating this, we can build a table showing all the possible outcomes:


\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right]

As we can see, of the 36 possible outcomes, 15 are greater than seven. So the probability is 15/36, which reduces to 5/12.

User Hillary
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