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3. Mr. Terence had 18 boxes containing 36 donuts each. He sold 162 donuts and

repacked the rest into 81 boxes. How many donuts did he put into cach box?​

User Pensu
by
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1 Answer

3 votes

6 donuts. He repacked 6 donuts into each box .

Mr. Terence had 18 boxes containing 36 donuts each, that means:

Total donuts = n° boxes*n° donuts

Total donuts = 18*36 = 648

He had in total 648 donuts.

He sold 162 donuts and repacked the rest into 81 boxes. Then:

Rest donuts = Total donuts - sold donuts

Rest donuts = 648 - 162 = 486

The rest donuts are 486 donuts.

He repacked the rest into 81 boxes, then:

n° donuts (each box) = Rest donuts/n° boxes

n° donuts (each box) = 486/81 = 6

The number of donuts that he put in each box is 6 donuts.

User HomerThinking
by
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