What are the roots of the equation {x}^(2) - 16x + 89 = 0 in simplest a+bi form?

asked Jun 28, 2020 212k views

1 vote

What are the roots of the equation

${x}^(2) - 16x + 89 = 0$
in simplest a+bi form?

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1 vote

By completing the square,

x^2-16x+89=x^2-16x+64+25=(x-8)^2+25=0

(x-8)^2=-25

$x-8=\pm√(-25)$

$x=8\pm5i$

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