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Find a1, for the given geometric series. Round to the nearest hundredth if necessary.

Sn= 88,560, r= 2.2, n= 6
a. 8,765.73
b. 2,477.6
c. 945.65
d. 14,754.5​

1 Answer

4 votes

Answer:

* The value of a1 = 945.65 ⇒ answer c

Explanation:

* Lets revise the geometric series

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5 , 10 , 20 , 40 , 80 , ………………………. (×2)

# 5000 , 1000 , 200 , 40 , …………………………(÷5)

* General term (nth term) of a Geometric Progression:

- U1 = a , U2 = ar , U3 = ar² , U4 = ar³ , U5 = ar^4

- Un = ar^n-1, where a is the first term , r is the constant ratio

between each two consecutive terms, n is the position

of the term

- The sum of first n terms of a Geometric series is calculate

from Sn = [a1 (1 - r^n)]/(1 - r) , where a1 is the first term, r is the

common ratio and n is the number of the terms

* Lets solve the problem

∵ Sn = 88,560

∵ r = 2.2

∵ n = 6

∵ Sn = [a1 (1 - r^n)]/(1 - r)

∴ 88,560 = [a1 (1 - 2.2^6)]/(1 - 2.2) ⇒ simplify up and down

∴ 88,560 = [a1 (-112.379904)]/(-1.2) ⇒ simplify the fraction

∴ 88,560 = a1 (93.64992) ⇒ divide both sides by 93.64992

∴ a1 = 945.6494998 ≅ 945.65

* The value of a1 = 945.65

User Husayn Hakeem
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