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Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the statement that could be true for h.

2 Answers

3 votes

Answer:

Both statements could be true because they satify the domain and range.

Explanation:

h(8)=19 has the domain of 8 and range of 19 which satisfies

a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25

h(-2)=2 has the domain of -2 and range of 2 which satisfies

a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25

User Zilicon
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Among the options, A (h(2) = 16) is the statement that fits within the given range and domain for the function h(x) and could be true.

The statement that is true of the domain

Given:

h(8) = 19

h(-2) = 2

Domain: -3 ≤ x ≤ 11

Range: 1 ≤ h(x) ≤ 25

A. h(2) = 16 - This value doesn't conflict with the range (1 ≤ h(x) ≤ 25) and fits within the given function's range and domain. It's a possible value for h(2) based on the constraints given.

B. h(8) = 21 - This contradicts the information provided (h(8) = 19).

C. f(13) = 18 - This option refers to a value outside the domain specified for h(x).

D. h(-3) = -1 - This value is outside the range provided for h(x) as the range starts from 1.

So, among the options, A (h(2) = 16) is the statement that fits within the given range and domain for the function h(x) and could be true.

Given that a function, h, has a domain of -3≤ x≤ 11 and a range of 1≤ h(x)≤ 25 and that h(8)=19 and h(-2)=2 , select the statement that could be true for h. A h(2)=16 B. h(8)=21 C. f(13)=18 D. h(-3)=-1

User Neal Barsch
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