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F(x)x^2-2x and g(x)=6x+4 for which value of x does (f+g)(x)=0

User Unixsmurf
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1 Answer

3 votes

Answer:

(f+g)(x)

Explanation:

(f+g)(x)=


{x}^(2) - 2x + 6x + 4 = {x}^(2) + 4x + 4


(x + 2)(x + 2) = 0


(x + 2) = 0 \\ x = - 2

User Mike Richards
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5.6k points
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