Answer:
46148 J
Step-by-step explanation:
You need to calculate the heat associated with each of the following steps. You will need to know some specific heats (they are probably given to you somewhere).
Step #1: Condensation
Step #2: Cooling from 100 C to 0 C
Step #3: Freezing
Step #4: Cooling from 0 C to -32 C
Step #1:
q = mC
q = 15 g (-2256 J/g )
q = -33840 J
Step #2:
q = mcΔT
q = 15 g (4.19 J/g/C)(-100 C)
q = 6285
Step #3:
q = mC
q = 15 g (-334 J/g)
q = -5010
Step #4:
q = mcΔT
q = 15 g (2.11 J/g/C)(-32 C)
q = -1013
Keep in mind the - signs indicate heat is being released. To calculate the total heat released, add the individual heats calcualted at each step:
Total heat released = 33840 + 6285 + 5010 + 1013 = 46148 J