Question

What are the x- and y-intercepts for the equation "2x + 3y = 6"?

(2,0) & (3,0)
(0, 2) & (3, 0)
(0,3) & (2,0)
(0,3) & (0,2)​

Answer 1

2x+3y=6
The answer is
(0,2) & (3,0)
You have to put 0 in the x then solve for y
After u get y replace the number in y and solve for x

Answer 2

(0,2) & (3,0)

Explanation:

Given the equation
`2x+3y=6`:

Step 1:

To find the y-intercept, you want to set the x value to zero. This will allow you to solve for y, and find where the equation intercepts why on the 0 line:

`2(0)+3y=6 \\ 0+3y=6\\ 3y=6\\ y=(6)/(3) \\  y = 2`

So, at x=0, y=2. or (0,2)

Step 2:

Set y = 0 and solve for x:

`2x+3(0)=6\\ 2x+0=6\\ 2x=6\\ x=(6)/(2)\\  x=3`

so at y=0, x=3. which is the same as saying: when x=3, y=0, or (3,0)