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Select the correct answer

A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could
possibly receive the tickets?

A.13
B.40
C.56
D.64

User Salouri
by
5.4k points

2 Answers

5 votes

Answer:

Answer is C.

Explanation:

The general formula for calculating combinations is:


(n!)/(k!(n-k)!)

Where n is the total number of options and k is the number of options in the combination.

In this case, sub in the numbers given in the question:


(8!)/(5!(8-5)!)


=(8* 7 * 6 )/(3 * 2)


=8 * 7


=56

User Massey
by
5.4k points
4 votes

Answer:

The correct answer option is C. 56.

Explanation:

We are given that a group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets.

We are to find the number of combinations these 5 friends could

possibly receive the tickets.

Here, we will use the concept of combination as the order of the friends is not specific.


5C5+ (5C4 * 3C1) + (5C3*3C2) + (5C2*3C3)


=1+5*3 + 10*3 +10*1 = 1+15+30+10= 56

User Dunno
by
5.6k points