Question

What are the solutions for x when y is equal to 0 in the following quadratic

function?

y = x ^+ 6x +12

OA) X = 3 or x = 4
OB) x= -3 or x = 4
OC) x= 3 or x = 4
OD) x= -3 or x = 4
O E) no solution​

Answer 1

The correct answer option is E) No solution.

Explanation:

We are given the following quadratic equation which we are to solve for x when the value of y is 0:

`y = x ^2+ 6x +12`

`x ^2+ 6x +12=0`

Using the quadratic formula since there are no factors:

`x=(-b \pm √(b^2-4ac ))/(2a)`

Substituting the values in the formula to get:

`x=(-6 \pm √(6^2-4(1)(12) ))/(2(1))`

`x=-3+√(3)i` or
`x=-3-√(3)i`

There are no real number solutions to this quadratic equation.