Question

What are the solutions of the following system?

Answer 1

Answer:(-6,312), (6,312)

Step by Step explanation:

• Solve the first equation for y.

10x^2-y=48

y=-48+10x^2

• Substitute the given value of y into the equation 2y=16x^2+48

2(-48+10x^2)=16x^2+48

Solve the equation for x.

x=-6

x=6

• Substitute the given value of x into the equation y=-48+10(-6)^

y=-48+10(-6)^2

y=-48+10×6^2

• Solve the equation for y

y=312

y=312