Answer:
B. 48
Explanation:
Use the property of secant and tangent to the circle: If one secant and one tangent are drawn to a circle from one exterior point, then the square of the length of the tangent is equal to the product of the external secant segment and the total length of the secant.
In yuor case,
Tangent = x
External secant = 6
Secant =6+2
So
![x^2 =6\cdot (2+6)\\ \\x^2 =6\cdot 8\\ \\x^2 =48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2gfperc5bnzytpbnt5qjnk3yk70b65ba5r.png)