Answer:
3%
Explanation:
We are given the data of number of cars observed waiting in line at the beginning of 2 minute intervals between 3 and 5 p.m. on Friday.
We are to find the probability (in percent) that there is no one in line.
Sum of frequencies = 2 + 9 + 16 + 12 + 8 + 6 + 4 + 2 + 1 = 60
Frequency of no car in line = 2
P (no car in line) = 2 / 60 × 100 = 3.3% ≈ 3%