Question

Find the nature of the quadratic equation 2x^2+5x+8=0​

Answer 1

`</p><p>2x^2+5x+8=0 \\</p><p>x=(-5+\vee-√(5^2-2\cdot2\cdot8))/(2\cdot2) \\</p><p>x=(-5+\vee-√(25-64))/(4) \\</p><p>x=(-5+\vee-√(-39))/(4)\Longrightarrow x\\otin\mathbb{R} \\</p><p>x\\otin\mathbb{R}\Longrightarrow x\in\mathbb{C}</p><p>`

So no real solutions for x. But two complex solutions for x.

`</p><p>x_1=\boxed{(-5-39i)/(4)} \\ \\</p><p>x_2=\boxed{(-5+39i)/(4)} </p><p>`

Hope this helps.

r3t40