Question

The circle below is centered at the point 4, 1 and has a radius of length 2 what is its equation​

Answer 1

`\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{4}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{2}{ r} \\\\\\ (x-4)^2+(y-1)^2=2^2\implies (x-4)^2+(y-1)^2=4`