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scores on a college entrance examination are normally distributed with a mean of 500 and a standard deviation of 100% of people who write this exam obtain scores between 425 and 575​

User Sabareesh
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1 Answer

4 votes

We have


\mu = 500


\sigma = 100

425 corresponds to a z of


z_1 = (425 - 500)/(100) = -\frac 3 4

575 corresponds to


z_2 = (575 - 500)/(100) = \frac 3 4

So we want the area of the standard Gaussian between -3/4 and 3/4.

We look up z in the standard normal table, the one that starts with 0 at z=0 and increases. That's the integral from 0 to z of the standard Gaussian.

For z=0.75 we get p=0.2734. So the probability, which is the integral from -3/4 to 3/4, is double that, 0.5468.

Answer: 55%

User Gslavin
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