Let's solve the inequalities: we have
![-(2)/(3)x<4 \iff -2x<12 \iff x>-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tbl5h6ixf4yx41ag08yuushx24ggbq9fnf.png)
and
![(3)/(4)x<-6 \iff 3x<-24 \iff x<-8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gg46hljoj0doje702kqg02csrsp5o0xp34.png)
Since the two inequality must be true at the same time (there is an "and" between the two), we should find a number that is, at the same time, greater than -6, and smaller than -8. But since -6 is greater than -8, a number greater than -6 is automatically greater than -8 as well. So, it is impossible for a number to be greater than -6 and smaller than -8.
If negative numbers confuse you, this example shows the same (impossible) logic: we can't ask for a number to be greater than 10, but smaller than 3.
As for the second exercise:
![3x-9\leq 9 \iff 3x \leq 18 \iff x \leq 6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/snau0duf8wylw5rdu56cd48n043ovyqjtc.png)
![4-x\leq 3 \iff -x \leq -1 \iff x \geq 1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yl6596nshrdddi1nys8mv8fpw9o29b2tod.png)
So, a number satisfies this system if it is smaller than 6 or greater than 1. This means that at least one of the conditions must be satisfied, and this is always the case:
- If we choose a number smaller than 1, the second condition is met
- If we choose a number between 1 and 6, both are met
- If we choose a number greater than 6, the first condition is met
So, whatever number we choose, at least one of the conditions will be true, and the logical "OR" will be satisfied.