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1 vote
I don’t understand why is it “not possible”.

-2/3x<4 and 3/4x<-6

And also I don’t understand why is it “all real numbers”.

3x-9≤9 or 4-x≤3

1 Answer

3 votes

Let's solve the inequalities: we have


-(2)/(3)x<4 \iff -2x<12 \iff x>-6

and


(3)/(4)x<-6 \iff 3x<-24 \iff x<-8

Since the two inequality must be true at the same time (there is an "and" between the two), we should find a number that is, at the same time, greater than -6, and smaller than -8. But since -6 is greater than -8, a number greater than -6 is automatically greater than -8 as well. So, it is impossible for a number to be greater than -6 and smaller than -8.

If negative numbers confuse you, this example shows the same (impossible) logic: we can't ask for a number to be greater than 10, but smaller than 3.

As for the second exercise:


3x-9\leq 9 \iff 3x \leq 18 \iff x \leq 6


4-x\leq 3 \iff -x \leq -1 \iff x \geq 1

So, a number satisfies this system if it is smaller than 6 or greater than 1. This means that at least one of the conditions must be satisfied, and this is always the case:

  1. If we choose a number smaller than 1, the second condition is met
  2. If we choose a number between 1 and 6, both are met
  3. If we choose a number greater than 6, the first condition is met

So, whatever number we choose, at least one of the conditions will be true, and the logical "OR" will be satisfied.

User Nerdar
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