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Solve the following system of equations

3x - 2y =5

-2x - 3y = 14

User Urdearboy
by
6.4k points

2 Answers

4 votes

Answer:

The solution is:


(-1, -4)

Explanation:

We have the following equations


3x - 2y =5


-2x - 3y = 14

To solve the system multiply by
(3)/(2) the second equation and add it to the first equation


-2*(3)/(2)x - 3(3)/(2)y = 14(3)/(2)


-3x - (9)/(2)y = 21


3x - 2y =5

---------------------------------------


-(13)/(2)y=26


y=-26*(2)/(13)


y=-4

Now substitute the value of y in any of the two equations and solve for x


-2x - 3(-4) = 14


-2x +12 = 14


-2x= 14-12


-2x=2


x=-1

The solution is:


(-1, -4)

User Alex Larikov
by
6.6k points
4 votes

Answer:

x = -1 and y = -4

Explanation:

It is given that,

3x - 2y = 5 ----(1)

-2x - 3y = 14 ------(2)

To find the solution of equations

(1) * 2 ⇒

6x - 4y = 10 -----(3)

(2) * 3 ⇒

-6x - 9y = 42 ----(4)

eq(3) + eq(4) ⇒

6x - 4y = 10 -----(3)

-6x - 9y = 42 ----(4)

0 - 13y = 52

y = 52/(-13) = -4

Substitute the value of y in eq(1)

3x - 2y = 5 ----(1)

3x - (2 * -4) = 5

3x +8 = 5

3x = 5 - 8 = -3

x = -3/3 = -1

Therefore x = -1 and y = -4

User Marc Khadpe
by
6.7k points