Question

Find The area of the trapezoid
Please help with questions 25-26

Answer 1

25) 96 cm²

26) 40.8 ft ²

Explanation:

25) To find the area of trapezoid

Area of trapezoid = h(a + b)/2

Here a = 6 + 12 + 2 = 20 cm

b = 12 cm and h = 6

Area = h(a + b)/2

= 6(20 + 12)/2

= 96 cm²

26) To find the area of kite

Area of kite = pq/2

Where p and q are the two diagonals

Here p = 10.2 ft and q = 8 ft

Area = pq/2

= (10.2 * 8)/2 = 40.8 ft²

Answer 2

Part 1)
`A=96\ cm^(2)`

part 2)
`A=40.8\ ft^(2)`

Explanation:

Part 1)

we know that

The area of a trapezoid is equal to

`A=(1/2)[b1+b2]h`

In this problem we have

`b1=12\ cm`

`b2=6+12+2=20\ cm`

`h=6\ cm` ----> perpendicular distance between the two bases

substitute

`A=(1/2)[12+20](6)`

`A=96\ cm^(2)`

Part 2)

we know that

The area of a kite is equal to

`A=(1/2)[D1*D2]`

we have

`D1=10.2\ ft`

`D2=8\ ft`

substitute

`A=(1/2)[10.2*8]`

`A=40.8\ ft^(2)`