204k views
2 votes
PLEASE HELP ME SUPER FAST IM STICK ON THESE 3!
See attachment below!

PLEASE HELP ME SUPER FAST IM STICK ON THESE 3! See attachment below!-example-1
PLEASE HELP ME SUPER FAST IM STICK ON THESE 3! See attachment below!-example-1
PLEASE HELP ME SUPER FAST IM STICK ON THESE 3! See attachment below!-example-2
User Asselin
by
5.3k points

2 Answers

5 votes

Answer:

25) 96 cm²

26) 40.8 ft ²

31). 6.0025π m²

Explanation:

25) To find the area of trapezoid

Area of trapezoid = h(a + b)/2

Here a = 6 + 12 + 2 = 20 cm

b = 12 cm and h = 6

Area = h(a + b)/2

= 6(20 + 12)/2

= 96 cm²

26) To find the area of kite

Area of kite = pq/2

Where p and q are the two diagonals

Here p = 10.2 ft and q = 8 ft

Area = pq/2

= (10.2 * 8)/2 = 40.8 ft²

31) To find the area of circle

Area of circle = πr²

Here r = 4.9/2 = 2.45 m

Area = πr²

= π *(2.45)²

= 6.0025π m²

User Marylu
by
6.3k points
2 votes

Answer:

25. The area of the trapezoid is 96 cm² ⇒ 2nd answer

26. The area of the kite is 40.8 feet² ⇒ 3rd answer

31. The area of the circle is 6.0025π m² ⇒ 3rd answer

Explanation:

* Lets solve the problems

25. The figure is trapezoid

- The trapezoid has two parallel bases base 1 and base 2

- The area of the trapezoid is 1/2(base 1 + base 2) × height

- The length of base 1 is 12 cm

- The length of its height is 6 cm

- The length of the base 2 is (2 + 12 + the adjacent side to ∠45°)

- To find the missing part in the base 2 use the trigonometry

function tan 45° = opposite/adjacent

∵ tan 45° = opposite/adjacent

∵ The opposite = 6

∵ tan 45° = 1

∴ 1 = 6/adjacent ⇒ by using cross multiplication

∴ The adjacent = 6 cm

∴ The length of base 2 = 2 + 12 + 6 = 20 cm

∵ The area of the trapezoid is 1/2(base 1 + base 2) × height

∵ The length of base 1 = 12 cm

∵ The length of base 2 = 20 cm

∵ The length of its height = 6 cm

∴ The area = 1/2(12 + 20) × 6 = 1/2(32) × 6 = 16 × 6 = 96 cm²

* The area of the trapezoid is 96 cm²

26. The figure is kite

- The kite has two diagonals

- Its diagonals perpendicular to each other

- The longest diagonal bisects the shortest diagonal

- The area of the kite is 1/2(diagonal 1 × diagonal 2)

∵ The length of diagonal 1 = 10.2 feet

∵ The length of diagonal 2 = 8 feet

∵ The area of the kite = 1/2(diagonal 1 × diagonal 2)

∴ The area = 1/2(10.2 × 8) = 1/2(81.6) = 40.8 feet²

* The area of the kite is 40.8 feet²

31. The figure is a circle

- The circle has diameter

- The radius is half the diameter

- The area of the circle is π r²

∵ The length of the diameter = 4.9 m

∵ The length of the radius 1/2 the length of the diameter

∴ The length of the radius = 1/2 (4.9) = 2.45 m

∵ The area of the circle = π r²

∴ The area = π (2.45)² = 6.0025π m²

* The area of the circle is 6.0025π m²

User Pratik Mhatre
by
6.1k points