Question

a mass suspended by a spring stretches an additional 4 ccm when an additional 10 gram mass is attached to it. what is the value of the spring constant k, in si units

Answer 1

2.45 N/m

Step-by-step explanation:

We can find the spring constant by using Hooke's law:

`F=kx`

where

F is the force applied to the spring

k is the spring constant

x is the stretching of the spring

Here, the force applied is the weight of the mass hanged on the spring. The mass is

m = 10 g = 0.010 kg

So the weight is

`F=mg=(0.010 kg)(9.8 m/s^2)=0.098 N`

while the stretching is

x = 4 cm = 0.04 m

So the spring constant is

`k=(F)/(x)=(0.098 N)/(0.04 m)=2.45 N/m`