Question

Find three consecutive even integers such that the sum is of the least and the middle is 48 more than the greatest

Answer 1

50, 52, and 54

Explanation:

The three even integers are x, x+2, and x+4. The sum of the least two is 48 more than the greatest:

x + x+2 = x+4 + 48

2x + 2 = x + 52

x = 50

So the three integers are 50, 52, and 54.