Question

The vertex of a quadratic function is located at (1,4) and the y-intercept of the function is (0,1). What is the value of a if the function is written in the form y=a(x-h)^2+k

Answer 1

-3

Explanation:

Took the quiz

Answer 2

a = -3

Explanation:

Put the y-intercept values into the equation and solve for a.

1 = a(0 -1)^2 +4 . . . . with (h, k) filled in, this is y=a(x-1)^2+4

-3 = a . . . . . . . . . subtract 4, simplify

The value of a is -3.