Answer:
The correct answer option is B. 60%.
Explanation:
We are given the results of a survey which asked the students whether they have any siblings and pets.
We are to determine the likelihood that student has a pet, given that he or she does not have a sibling.
Assuming A to be the event showing that a student does not have a sibling and B to be the event that a students has a pet.
Then P(B|A) is:
![P(B|A)=(P(A\bigcap B))/(P(A))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/au80dp3bav0tybttdmj6gocmkuv3n188t2.png)
Substituting the given values, P(A)=0.25 and P(A∩B)=0.15:
![P(B|A)=(0.15)/(0.25)\\\\P(B|A)=(3)/(5)\\\\P(B|A)=0.6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ya336yv4p6nh1b58167g6l4k5m0vy5joxx.png)
So the percentage will be:
60%