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To the nearest hundredth of a centimeter, what is the length of a leg of the triangle?

[1] cm
84.6 cm

To the nearest hundredth of a centimeter, what is the length of a leg of the triangle-example-1
User Luca T
by
8.6k points

2 Answers

6 votes

Answer:

The length of a leg of the triangle = 59.83 cm

Explanation:

Points to remember

If a right angled triangle with angles 45°, 45° and 90° then the sides are in ratio 1 : 1 : √2

It is given a right angled triangle with 45°, 45° and 90° and hypotenuse = 84.6 cm

To find the length of a leg

Let 'x' be the length of each leg,

From the figure we can write,

1: 1 : √2 = x : x : 84.6

Therefore x = 84.6/√2

= 59.83 cm

Therefore the length of a leg of the triangle = 59.83 cm

User Johannes Lumpe
by
8.2k points
3 votes

ANSWER

59.82

EXPLANATION

The given right angle is an isosceles right triangle.

Let the length of a leg be x cm.

Then by the Pythagoras Theorem,


{x}^(2) + {x}^(2) = 84.6 ^(2)


2 {x}^(2) = 7157.16

Divide both sides by 2.


{x}^(2) = (7157.16)/(2)


{x}^(2) = 3578.58

Take positive square root of both sides to get,


x = 59.82123369

Hence the length of a leg is 59.82 to the nearest hundredth.

User Trbck
by
7.4k points

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