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M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of colors for plain M&M candies is as follows.

Color Purple Yellow Red Orange Green Blue Brown
Percentage 17% 18% 17% 7% 6% 10% 25%

Suppose you have a large bag of plain M&M candies and you choose one candy at random.

a. Find P(green candy or blue candy).
b. Are these outcomes mutually exclusive? Why?

1 Answer

3 votes

Answer:


P(Green\ candy\ or\ Blue\ candy) = 0.16

Yes, they are mutually exclusive

Explanation:

Given

Refer to the table in the question

Solving (a): P(green candy or blue candy)

This is calculated as:


P(Green\ candy\ or\ Blue\ candy) = P(Green) + P(Blue)

From the question:


P(Blue) = 10\%


P(Green) = 6\%

So:


P(Green\ candy\ or\ Blue\ candy) = P(Green) + P(Blue)


P(Green\ candy\ or\ Blue\ candy) = 6\% + 10\%


P(Green\ candy\ or\ Blue\ candy) = 16\%

Convert to decimal


P(Green\ candy\ or\ Blue\ candy) = 0.16

Solving (b): Are they mutually exclusive?

Multiple events A and B are mutually exclusive if;


P(A\ or\ B) = P(A) + P(B)

In (a) above:


P(Green\ candy\ or\ Blue\ candy) = P(Green) + P(Blue)

and this is so every other possible colour of candy

e.g.


P(Red\ or\ Yellow) = P(Red) + P(Yellow)

Hence:

The events are mutually exclusive

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