Question

Please help on this one?

Answer 1

C

Step-by-step explanation:

Answer 2

`\text{C. } _(36)^(85)\text{Kr}`

Step-by-step explanation:

Your nuclear equation is

`_(35)^(85)\text{Br} \longrightarrow \, _(-1)^(0)\text{e} +\, _(x)^(y)\text{X}`

The main point to remember in balancing nuclear equations is that

• the sum of the superscripts and must be the same on each side of the equation.
• the sum of the subscripts must be the same on each side of the equation.

Then

85 = 0 + y, so y = 85 - 0 = 0

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.

The nuclear equation becomes

`_(35)^(85)\text{Br} \longrightarrow \, _(-1)^(0)\text{e} + \, _(36)^(85)\text{Kr}`