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Find the average value of y equals the square root of the quantity 64 minus x squared, on its domain.

1 Answer

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Answer:

2π ≈ 6.283

Explanation:

The average value of the function is the area under it, divided by the base. This function describes a semicircle of radius 8, so its area is ...

A = 1/2πr² = 1/2π·8² = 32π

The width of the base is the diameter of the semicircle, so is 16. Then the average value is ...

32π/16 = 2π . . . . . average value of y

Find the average value of y equals the square root of the quantity 64 minus x squared-example-1
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