Question

Can someone help me please

Answer 1

For this case we must indicate an expression equivalent to:

`x + 2 + [4x- \frac {x ^ 2 + 6x + 8} {x + 4}]`

If we factor the quadratic expression, we must find two numbers that when multiplied give as result 8, and when summed give as result 6. These numbers are 4 and 2. Then:

`x ^ 2 + 6x + 8 = (x + 2) (x + 4)`

Rewriting the expression:

`x + 2 + [4x- \frac {(x + 2) (x + 4)} {(x + 4)}] =`

Simplifying common terms we have:

`x + 2 + [4x- (x + 2)] =`

Taking into account that:

`- * + = -\\x + 2 + 4x-x-2 =\\x-x + 2-2 + 4x =\\4x`

ANswer:

4x