Question

Solve the system .....................​

Answer 1

first option

(2, 3)

Explanation:

We have the following system of linear equations

`\left \{{{3y=-x+11} \atop {x+4y=14}} \right.`

This is the same as

`\left \{{{x + 3y=11} \atop {x+4y=14}} \right.`

To solve the system multiply the first equation by -1 and then add it to the second equation.

`-1*(x+3y)=11*(-1)`

`-x -3y=-11\\x+4y=14`

-----------------

`y = 14-11`

`y = 3`

substitute
`y = 3` in any of the two equations and then solve for x

`x+4(3)=14\\x+12=14\\x =14-12\\x = 2\\`

`x =2`

The answer is the first option

(2, 3)

Answer 2

The correct answer is first option

(2, 3)

Explanation:

It is given that,

3y = -x + 11 and

x + 4y = 14

To find the solutions

The given equation can be written as,

x + 3y = 11 --------(1)

x + 4y = 14 -------(2)

Subtract (1) from (2) we get

y = 3

Substitute vale of y in eq(1)

x + 3*3 = 11

x = 11 - 9 = 2

Therefore x = 2 and y = 3

The correct answer is first option