Question

The average house in a neighborhood measures 55 ft by 35 ft by 20 ft tall. What is the total outside surface area?

Answer 1

`\bf \textit{surface area of a rectangular prism}\\\\ SA=2(Lh+Lw+wh)~~ \begin{cases} L=length\\ w=width\\ h=height\\ \cline{1-1} L=55\\ w=35\\ h=20 \end{cases} \\\\\\ SA=2[(55\cdot 20)+(55\cdot 35)+(35\cdot 20)]\implies SA=2[1100+1925+700] \\\\\\ SA=2(3725)\implies SA=7450`