Question

Find the slope of a line perpendicular to 2y = -6x +8

Answer 1

`\bf 2y=-6x+8\implies y=\cfrac{-6x+8}{2}\implies y=\cfrac{-6x}{2}+\cfrac{8}{2} \\\\\\ y=-3x+4\impliedby \begin{array}ll \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill`

`\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-3\implies -\cfrac{3}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{1}{3}}\qquad \stackrel{negative~reciprocal}{+\cfrac{1}{3}\implies \cfrac{1}{3}}}`