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In ∆BCD if BC=BD, m<B=(13x-35)°, m<C=(5x-19)°, and m<D=(2x+14)°, find x and the measure of each angle​

User Danblack
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1 Answer

5 votes
5 votes

Answer:

Value of x = 11 ° , ∠B = 108° ,∠C = 36° ,∠D = 36°

Explanation:

Given :

In ΔBCD , BC = BD And ∠B= (13x-35)° , ∠C= (5x-19)° ,∠D=(2x+14)°

To Find :

value of x and ∠D , ∠B and ∠C

Solution:

∵ BC=BD , So ∠C = ∠D

Therefore 5x-19 = 2x+14

3x = 33 , ∴ x=11°

So, ∠B = (13×11) - 35 = 108°

∠C = (5×11)-19 = 36°

∠D= (2×11) +14 =36°

User Xrnd
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