Question

What is the greatest common factor of 8m, 36m3, and 12

Answer 1

Answer:
`GCF=4`

Explanation:

To find the Greatest Common Factor (GCF) of 8m, 36m³, and 12, you need to descompose them into their prime factors. Then:

`8m=2*2*2*m=2^3*m\\\\36m^3=2*2*3*3*m^3=2^2*3^2*m^3\\\\12=2*2*3=2^2*3`

You can observe that the common factor with the lowest exponent is the following:

`2^2`

Therefore, the Greatest Common Factor (GCF) of 8m, 36m³, and 12 is:

`GCF=2^2\\GCF=4`

Answer 2

GCF=4

EXPLANATION

The given monomials are:

`8m = {2}^(3) m`

`36 {m}^(3) = {2}^(2) * {3}^(2) {m}^(3)`

`12 = {2}^(2) * 3`

The greatest common factor is the product of all the least powers of the common factors.

We can see that:

`{2}^(2)`

is the common to all the factors.

Therefore the greatest common factor is

`{2}^(2) = 4`