Answer:
It's choice D.
Explanation:
(f + g)(x) = f(x) + g(x)
= 3x - 2 + x^2 + 1
= x^2 + 3x - 1.
D. x^2+3x-1
You have:
f(x) = 3x-2
g(x)= x^2 +1
Then:
(f+g)(x)=f(x)+g(x)
(f+g)(x)=(3x-2)+(x^2+1)
(f+g)(x)=3x-1+x^2 (-2+1=-1)
(f+g)(x)=x^2+3x-1 (ordering terms)
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