Question

What is the equation of (4,10),(6,11) in standard form?​

Answer 1

The standard form is:

`x - 2y = - 16`

Step-by-step explanation

The given line passes through (4,10)and (6,11).

The slope of this line is

`m = (11 - 10)/(6 - 4)`

`m = (1)/(2)`

The equation is given by the formula,

`y-y_1=m(x-x_1)`

We plug in the first point and the slope to get.

`y-10= (1)/(2) (x-4)`

`2y - 20 = x - 4`

`x - 2y = - 20 + 4`

`x - 2y = - 16`

The standard form is

`x - 2y = - 16`