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What is the center of the circle that has a diameter whose endpoints are(5, -6) and (-1, -8)?

User Jny
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2 Answers

4 votes

Answer:

(2, -7).

Explanation:

The center is the midpoint of the diameter.

This is (5 + -1) / 2 , (-6+(-8)/2)

= (4/2, -14/2)

= (2, -7).

User Noam Ross
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4.4k points
7 votes

Answer: The center is (2,-7)

Explanation:

In this case the center of this circle is the midpoint of its diameter. Then you need to use this formula:


Midpoint=Center=((x_1+x_2)/(2),(y_1+y_2)/(2))

Knowing that this circle has a diameter whose endpoints are (5, -6) and (-1, -8), you can identify that:


x_1=5\\x_2=-1\\y_1=-6\\y_2=-8

Then you can substitute these coordinates into
Center=((x_1+x_2)/(2),(y_1+y_2)/(2)), getting:


Center=((5+(-1))/(2),(-6+(-8))/(2))


Center=((5-1)/(2),(-6-8)/(2))


Center=(2,-7)

User Adalberto
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